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Ihor Kendiukhov

๐Ÿ‘ค Speaker
515 total appearances

Appearances Over Time

Podcast Appearances

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

You can bet on the color of a drawn ball.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

Most people prefer betting on red, known probability of one-third, over betting on black, unknown probability, could be anything from zero to two-thirds, even though if you assign your best estimate probability of one-third to black, the expected values are identical.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

This is typically treated as another irrational bias.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

The probabilities are the same in expectation, so why should ambiguity matter?

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

Ergodicity economics provides a natural and I think quite elegant resolution, and it comes in two layers.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

The first layer is a direct Jensen's inequality argument.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

Under multiplicative dynamics, the time average growth rate of a repeated gamble is a concave function of the probability.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

For a simple multiplicative bet with fraction f of wealth wagered, the growth rate is something like g p equals p asterisk log 1 plus f plus 1p asterisk log 1f, which is concave in p. Now consider the Ellsberg un.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

the number of black balls could be 0, 1, 2, 60.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

If you are maximally uncertain and average uniformly over these possibilities, the expected proportion is 30 divided by 60 equals 1 half, which matches the known probability case.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

An ensemble average reasoner sees no difference.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

E in P equals one half in both cases, so the expected value of the gamble is the same.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

But concavity of G in P means that Jensen's inequality applies.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

EGP less than GEP.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

The average time-average growth rate across all possible earned compositions is strictly less than the time-average growth rate you get when the probability is known to be one-half.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

Each distinct earned composition, zero black balls, one black ball, two black balls, and so on, defines a different multiplicative process with a different time-average growth rate.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

You can compute all 61 of these growth rates and average them, and that average will be strictly lower than the single growth rate corresponding to the known one-half probability because you are averaging a concave function.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

The gap is mathematically inevitable, and it is completely invisible to ensemble averaging.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

The second layer is about strategic optimality.

LessWrong (Curated & Popular)
"On Independence Axiom" by Ihor Kendiukhov

Even beyond the Jensen's inequality point, an agent under multiplicative dynamics has a further reason to prefer known probabilities.