Ivette Fuentes

speaker

347 appearances 1 recordings 1 series first heard Nov 2025 last heard 25 Nov

Ivette Fuentes’s voice in public audio — every appearance, attributed to the second.

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Recordings per month over the last 12 months — 1 in all, peaking in Nov 2025 with 1.

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Theories of Everything with Curt Jaimungal · Roger Penrose and Ivette Fuentes: A Bold New Test of Gravity · 25 Nov 2025 podcast

We we wrote this paper on what could you do with a Bose Einstein condensate because could we use as an advantage that you can cool it down to those temperatures?

But now here comes uh the the big problem is that if you take a Bose Einstein condensate, what you want to do to test uh gravity is that you want to create a superposition of uh the atoms left and right.

Actually I didn't say what a Bose Einstein condensate.

Say this, maybe I should start there.

So take an atom in a well and cool it down to the ground state.

So that you do in second-year quantum mechanics is the typical example.

And it's really beautiful because what you see when you cool down the atom to the ground state is that it becomes completely delocalized in the potential.

So it's not just like left or right, it's like everywhere.

Now take uh a

ten to the five.

That's like a the typical size of a boson condensate for most experiments.

Ten to the five, ten to the six, rubidium, sodium, something like this, atoms into the ground state.

So the s system because atoms are bosons,

the the system be behaves like a big macroscopic uh system behaving quantum mechanically.

So that's very nice and people use them for many things.

But now the challenge is take the ten to the six to we need ten to the nine actually to to create a superposition of left and right.

And that is very difficult because a Bose Einstein condensate is not a solid, it's a fluid.

So in particular the atoms are not bounded uh together.

And the moment that you lose one single atom from this superposition, all of them left, plus all of them down, that left and right, so you would do this in what we call a double well potential.

So P

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